x^2+3x-5=2x^2+5x-4

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Solution for x^2+3x-5=2x^2+5x-4 equation: 



x^2+3x-5=2x^2+5x-4

We move all terms to the left:

x^2+3x-5-(2x^2+5x-4)=0

We get rid of parentheses

x^2-2x^2+3x-5x+4-5=0

We add all the numbers together, and all the variables

-1x^2-2x-1=0

a = -1; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·(-1)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{2}{-2}=-1$

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